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summary of an 'inflexible knowledge' moment & how I tried to work through it
tentative conclusionsBasically, everything we read & hear about learning math from cognitive psychologists, mathematicians, & experienced non-constructivist teachers happened here.
My notes are below. trying to figure out how to do a percent decrease problem in an unfamiliar formatOK, I'm trying to figure out what percent decrease it is when you drop from 22% of Michigan students scoring a 4 (for advanced or exceeds standards) down to 9 percent. sequence of events
This, to me, is an example of inflexible knowledge, because I can't tell whether I can transfer the formula I know (and do have some conceptual understanding of, believe it or not) to this new situation. I can't even tell if this is a new situation. My first impulse was to look it up in ALGEBRA TO GO. Unfortunately--or fortunately--ALGEBRA TO GO only has examples using the raw data, not the percents. Then it occurred to me that I ought to see if I can work this out myself.....and that the way to do that is.... I know! WORK BACKWARDS!also: MAKE IT SIMPLE!It's so fun, here in midlife, being a Rank Amateur at elementary math.I'll be back. Alright. My first thought came pretty quickly, which I think is good, because I think it shows some gains in flexible knowledge. I was sitting here staring at my notebook when it suddenly struck me that since I'm hung up on raw data numbers versus percent numbers, I ought to simply translate the problem into '22 students' versus '9 students.' So I did. I subtracted 9 from 22 & got 13. Then I divided 13 by the original 22 to find out the percent decrease and came up with an answer of 59%. (I'm sorry, that's big. I may know NOTHING about elementary math, but a 59% decrease is big.) At this point it struck me that I should check ALGEBRA TO GO to make sure I'm do have the math correct for raw data-type numbers. The problem they give for figuring percent decrease is a drop in gas prices from $1.24 to $1.19. (Pub date on this book is 2000.) Alright, I'm going to see if I do the calculations right..... Yup! I got it. $1.24 - 1.19 = .05 .05 1.24 = 4 percent.
ALGEBRA TO GO gives 4 percent as the answer.
speed with doubtnote: I did not feel particularly confident working this problem, but OTOH, I could do it, and I could do it pretty quickly. I'm assuming that speed-with-doubt is midway to flexible knowledge, since my starting point on problems I have no clue how to do is doubt-with-paralysis.[pause] I'm back. This next part is embarrassing, but what the heck. I looked at my gasoline problem and thought: can I rewrite the two gas prices as percents and see if I get the same answer? I felt I couldn't do that, because a percent 'has to be' between 0 and 100 to be a percent, and both $1.24 and $1.19 are greater than 100. My very next thought, thanks to Saxon Math, was Don't be a moron, of course a percent can be greater than 100!. This is another example of inflexible knowledge. I'm used to seeing percent numbers from 0 to 100, and a percent of 125% throws me. However, that recognition didn't do me much good; I was starting to feel dazed. So I decided to go back to my 9 and 22, both of which numbers are, indeed, less than 100. Looking at 9 and 22, it now strikes me that the formula for finding percent decrease using percents has to be the same as the formula for finding percent decreases using raw data. I don't feel confident of this conclusion, but I do think it's right. Assuming it is right, I had another boost from SAXON MATH, which is the various lessons that have you do the four operations on percent numbers. I can't remember the lessons now, but my memory is that they ask the student to perform the operations on percent figures even when it's a bit unwieldy to do so, because they want you to perceive that like can be added to, subtracted from, multplied, or divided by like. Those lessons made a big impression on me, because apparently I had never been taught this during my own childhood. (Christopher was impatient with these lessons.) So....it struck me that if the percentage decrease from 22 students to 9 students is 59%, the percentage decrease from 22% to 9% also has to be 59%. At that point it crossed my mind simply to take a look at the numbers, and see if an answer of 59% made sense. It does. When I look at the numbers.....I see that 9 is semi-in-the-realm of being 1/3 of 22....and that 59% is semi-in-the-realm of being 2/3 of 22.....in other words, just staring at these numbers I feel that only about 1/3 of the number of kids who used to get 4s are now getting 4s, which means 2/3 of the kids are not, which would be in the neighborhood of a 59% decrease. I'm also using a compare-and-contrast approach that I think math books don't give enough attention to. Back when I first wanted to learn how to figure percent increases and percent decreases because I wanted to figure out the percent decrease in 4s in Scarsdale schools using TRAILBLAZERS, a friend told me the way to figure it was just to subtract the lower percent figure from the higher percent figure, because 'you can subtract like from like.' I had come far enough in math knowledge to feel that was wrong.....and to semi-intuit that there would have to be another division step after the subtraction. At that point, I looked it up in ALGEBRA TO GO (which I think in that case was the correct response. LEARN HOW TO LEARN, BABY!) So just now I eyeballed this problem to see what the two different answers would be, one answer a simple subtraction of 9% from 22%, the other answer the quotient of the difference divided by the original percent. The two answers are very different: 13% versus 59% Eyeballing the problem, 13% seems obviously wrong. That gives me slightly more confidence that 59% is right. I'm going to summarize this in bullet points at the top of the page-- -- CatherineJohnson - 13 Jul 2005 CommentsAfter entering a comment, users can login anonymously as KtmGuest (password: guest) when prompted.Please consider registering as a regular user. Look here for syntax help. Back to: Main Page. |