Solutions to the problems posted on SingaporeWordProblemSampler2

Primary 3:

Subtract 3 quarts and 3 cups from 9 quarts. You have to 'borrow' a quart and convert it to 4 cups.

9 q. - 3 q. 3 c. =
8 q. 4 c. - 3 q. 3 c.=
5 q. 1 c.

Primary 4:

I thought this problem was a little weird, but I think the solution is:

5/9 - 2/9 = 3/9 (1/3) more chocolates are round than square.

Primary 5:

To set this problem up algebraically, let m be the number of stickers Martin has, and let g be the number of stickers that Gary has.

They have 80 stickers altogether, so m + g = 80.

After Martin gives away 35 stickers, he has m - 35 stickers left; and after Gary gives away 1/5 of his stickers, he has 4/5 left.

These quantities are equal, so m - 35= 4/5 g.

Now we have two unknowns, and two equations, so we are ready to solve the problem. Substitute m = 80- g from the first equation into the second equation, to get: (80- g) - 35= 4/5 g , or 45 - g = 4/5 g.

Solving this equation gives g = 25, so m = 55: Martin originally had 55 stickers.

Primary 6:

The basic equation used here is distance = rate x time (the " rt=d " equation).

We are told that Jane is 140 miles away from Point Q when Linda arrives, and it takes her two more hours to get there. So her rate must be the distance she traveled over the time it required: 140 km / 2 hr = 70 km/hr.

We know the whole trip was 630 miles, and if Jane traveled that distance at 70 km/hour, it must have taken her 9 hours (using the rt=d equation again).

We then know that the trip took Linda 7 hours, because it took Jane two more hours than Linda to get to City Q. So she traveled 630 km in 7 hours, and her speed must have been 90 km/hr, using the rt=d equation again.

-- CarolynJohnston - 02 Jul 2005

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